Identify the total number of monochlorinated | vedclass

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(A) The structure of $2$-methylpentane is $CH_3-CH(CH_3)-CH_2-CH_2-CH_3$. There are $5$ distinct types of hydrogen atoms in the molecule: $1$. The $CH

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$5$

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(A) The structure of $2$-methylpentane is $CH_3-CH(CH_3)-CH_2-CH_2-CH_3$. There are $5$ distinct types of hydrogen atoms in the molecule: $1$. The $CH_3$ group attached to $C_2$ (position $1$). $2$. The $CH$ group at $C_2$ (position $2$). $3$. The $CH_2$ group at $C_3$ (position $3$). $4$. The $CH_2$ group at $C_4$ (position $4$). $5$. The $CH_3$ group at $C_5$ (position $5$). Since there are $5$ non-equivalent hydrogen atoms,replacing any one of them with a chlorine atom will result in a unique monochlorinated product. Note that the two $CH_3$ groups at the $C_2$ position are equivalent. Therefore,the total number of monochlorinated products is $5$.

Identify the total number of monochlorinated products formed when $2$-methylpentane reacts with $Cl_2 / hv$.

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